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7n^2-61n-40=0
a = 7; b = -61; c = -40;
Δ = b2-4ac
Δ = -612-4·7·(-40)
Δ = 4841
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$n_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$n_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$n_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-61)-\sqrt{4841}}{2*7}=\frac{61-\sqrt{4841}}{14} $$n_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-61)+\sqrt{4841}}{2*7}=\frac{61+\sqrt{4841}}{14} $
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